LeetCode Intersection of Two Linked Lists 解题报告

标签：leetcode解题报告   算法   java   链表   

A:          a1 → a2
                   ↘
                     c1 → c2 → c3
                   ↗            
B:     b1 → b2 → b3

public class Solution {
    
    public ListNode getIntersectionNode(ListNode headA, ListNode headB) {
        if(headA==null||headB==null) {
            return null;
        }
        int lengthA = 1;
        int lengthB = 1;
        
        ListNode iterA = headA;
        while(iterA.next!=null) {
            iterA = iterA.next;
            lengthA++;
        }
        
        ListNode iterB = headB;
        while(iterB.next!=null) {
            iterB = iterB.next;
            lengthB++;
        }
        
        if(iterA!=iterB) {
            return null;
        }
        
        if(lengthA>lengthB) {
            int tmp = lengthA - lengthB;
            while(tmp>0) {
                headA = headA.next;
                tmp--;
            }
        } else {
            int tmp = lengthB - lengthA;
            while(tmp>0) {
                headB = headB.next;
                tmp--;
            }
        }
        
        
        
        
        while(headA!=headB) {
            headA = headA.next;
            headB = headB.next;
        }
        
        return headA;
    }
}

LeetCode Intersection of Two Linked Lists 解题报告

标签：leetcode解题报告   算法   java   链表   

原文地址：http://blog.csdn.net/worldwindjp/article/details/42225921