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九度OJ 1092 Fibonacci

时间:2014-12-29 01:23:53      阅读:177      评论:0      收藏:0      [点我收藏+]

标签:九度oj   1092   

题目1092:Fibonacci

时间限制:1 秒

内存限制:32 兆

特殊判题:

提交:1576

解决:1158

题目描述:

    The Fibonacci Numbers{0,1,1,2,3,5,8,13,21,34,55...} are defined by the recurrence: 
    F0=0 F1=1 Fn=Fn-1+Fn-2,n>=2 
    Write a program to calculate the Fibonacci Numbers.

输入:

    Each case contains a number n and you are expected to calculate Fn.(0<=n<=30) 。

输出:

   For each case, print a number Fn on a separate line,which means the nth Fibonacci Number.

样例输入:
1
样例输出:
1

#include<stdio.h>
int f[40];
int main(int argc, char *argv[])
{
    f[0]=0;
    f[1]=1;
    for(int i=2;i<=30;++i)
        f[i]=f[i-1]+f[i-2];
    int n;
    while(~scanf("%d",&n))
    {
        printf("%d\n",f[n]);
    }
    return 0;
}
 
/**************************************************************
    Problem: 1092
    User: kirchhoff
    Language: C
    Result: Accepted
    Time:0 ms
    Memory:912 kb
****************************************************************/



九度OJ 1092 Fibonacci

标签:九度oj   1092   

原文地址:http://blog.csdn.net/wdkirchhoff/article/details/42218197

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