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DP.类似最大和。就是要记录正的和负的两种情况。
class Solution {
public:
int maxProduct(int A[], int n) {
vector<int> positive(n);
vector<int> minus(n);
int result = A[0];
for (int i = 0; i < n; i++) {
int minVal = A[i];
int maxVal = A[i];
if (i > 0) {
minVal = min(minVal, positive[i - 1] * A[i]);
minVal = min(minVal, minus[i - 1] * A[i]);
maxVal = max(maxVal, positive[i - 1] * A[i]);
maxVal = max(maxVal, minus[i - 1] * A[i]);
}
positive[i] = maxVal > 0 ? maxVal : 1;
minus[i] = minVal < 0 ? minVal : 1;
result = max(result, maxVal);
}
return result;
}
};
[leetcode]Maximum Product Subarray
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原文地址:http://www.cnblogs.com/lautsie/p/4196797.html