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用分桶的做法,思路参考自网友,很精妙。
class Solution { public: int maximumGap(vector<int> &num) { int size = num.size(); if (size < 2) { return 0; } int maxVal = *max_element(num.begin(), num.end()); int minVal = *min_element(num.begin(), num.end()); int gap = (maxVal - minVal - 1) / (size - 1) + 1; // ceiling function int bucketSize = (maxVal - minVal) / gap; vector<int> minBucket(bucketSize, INT_MAX); vector<int> maxBucket(bucketSize, INT_MIN); for (int i = 0; i < size; i++) { if (num[i] == minVal || num[i] == maxVal) { continue; } int idx = (num[i] - minVal) / gap; minBucket[idx] = min(minBucket[idx], num[i]); maxBucket[idx] = max(maxBucket[idx], num[i]); } int maxGap = INT_MIN; int prev = minVal; for (int i = 0; i < bucketSize; i++) { if (minBucket[i] != INT_MAX) { maxGap = max(maxGap, minBucket[i] - prev); prev = maxBucket[i]; } } maxGap = max(maxGap, maxVal - prev); return maxGap; } };
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原文地址:http://www.cnblogs.com/lautsie/p/4196780.html