标签：c++   uva   

                         uva 784 Maze Exploration

A maze(迷宫) of rectangular(矩形的) rooms is represented on a two dimensional(空间的) grid as illustrated(阐明) in figure 1a. Each point of the grid is represented by a character. The points of room walls are marked by the same character which can be any printable(印得出的) character different than `*‘, `_‘ and space. In figure 1 this character is `X‘. All the other points of the grid are marked by spaces.

               XXXXXXXXXXXXXXXXXXXXX             XXXXXXXXXXXXXXXXXXXXX
               X   X   X   X   X   X             X###X###X###X   X   X
               X           X   X   X             X###########X   X   X
               X   X   X   X   X   X             X###X###X###X   X   X
               XXXXXX XXX XXXXXXXXXX             XXXXXX#XXX#XXXXXXXXXX
               X   X   X   X   X   X             X   X###X###X###X###X
               X   X     *         X             X   X###############X
               X   X   X   X   X   X             X   X###X###X###X###X
               XXXXXXXXXXXXXXXXXXXXX             XXXXXXXXXXXXXXXXXXXXX

All rooms of the maze are equal sized with all walls 3 points wide and 1 point thick as illustrated(阐明) in figure 2. In addition, a wall is shared on its full length by the separated rooms. The rooms can communicate through doors, which are positioned in the middle of walls. There are no outdoor doors.

                     door
                       |
                     XX XX
                     X . X   measured from within the room
               door - ...--  walls are 3 points wide
                     X . X__
                     XXXXX  |
                       |___  walls are one point thick

Your problem is to paint all rooms of a maze which can be visited starting from a given room, called the `start room‘ which is marked by a star (`*‘) positioned in the middle of the room. A room can be visited from another room if there is a door on the wall which separates the rooms. By convention(大会), a room is painted if its entire surface, including the doors, is marked by the character `#‘ as shown in figure 1b.

Input 

1.

The first line contains a positive(积极的) integer(整数) which shows the number of mazes to be painted.

2.

The rest of the file contains the mazes.

The lines of the input file can be of different length. The text which represents a maze is terminated(终止) by a separation line full of underscores(底线) (`_‘). There are at most 30 lines and at most 80 characters in a line for each maze(迷宫)

The program reads the mazes from the input(投入) file, paints them and writes the painted mazes on the standard output(输出).

Output 

Sample Input 

2
XXXXXXXXX
X   X   X
X *     X
X   X   X
XXXXXXXXX
X   X
X   X
X   X
XXXXX
_____
XXXXX
X   X
X * X
X   X
XXXXX
_____

Sample Output 

XXXXXXXXX
X###X###X
X#######X
X###X###X
XXXXXXXXX
X   X
X   X
X   X
XXXXX
_____
XXXXX
X###X
X###X
X###X
XXXXX
_____

题目大意：将可以走到的地方标记成‘#‘(下划线是终止一组数据）

解题思路：DFS遍历的同时直接修改map.

#include<stdio.h>
#include<string.h>
char map[35][85], cnt = 0;
void DFS(int a, int b) {
	map[a][b] = '#';
	for (int i = -1; i <= 1; i++) {
		for (int j = -1; j <= 1; j++) {
			if (i == 0 && j == 0) {
				continue;
			}
			if (a + i < 0 || a + i > cnt) {
				continue;
			}	
			if (b + j < 0 || b + j > strlen(map[a + i])) {
				continue;
			}
			if (map[a + i][b + j] == '#' || map[a + i][b + j] == 'X') {
				continue;
			}
			DFS(a + i, b + j);
		}
	}
}	
int main() {
	int n;
	scanf("%d\n", &n);
	while (n--) {
		memset(map, 0, sizeof(map));
		cnt = 0;
		while (gets(map[cnt]) != NULL) {  
			if (strcmp(map[cnt], "_____") == 0) { 
				break;  
			}
			cnt++;  
		}
		for (int i = 0; i <= cnt; i++) {
			for (int j = 0; j < strlen(map[i]); j++) {
				if (map[i][j] == '*') {
					DFS(i, j);
				}
			}
		}
		for (int i = 0; i <= cnt; i++) {
			puts(map[i]);
		}
	}
	return 0;
}

uva 784 Maze Exploration（DFS遍历图）

标签：c++   uva   

原文地址：http://blog.csdn.net/llx523113241/article/details/42319217