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【leetcode】Container With Most Water

时间:2015-01-03 15:52:26      阅读:129      评论:0      收藏:0      [点我收藏+]

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Container With Most Water

Given n non-negative integers a1a2, ..., an, where each represents a point at coordinate (iai). n vertical lines are drawn such that the two endpoints of line i is at (iai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

Note: You may not slant the container.

 
 
利用p1,p2标识height[0]和height[n-1]
比较两者的大小,如果height[p1]>=height[p2],则p2--,否则p1++
(如果height[p1]>=height[p2]时,我们让p1++,这样是没有意义的,后续求的所有面积必然比当前的要小)
  
 
 1 class Solution {
 2 public:
 3     int maxArea(vector<int> &height) {
 4        
 5         int n=height.size();
 6         int p1=0;
 7         int p2=n-1;
 8        
 9         int maxArea=0;
10         while(p1<p2)
11         {
12             int area;
13             if(height[p1]>=height[p2])
14             {
15                 area=(p2-p1)*height[p2];
16                 p2--;
17             }
18             else
19             {
20                 area=(p2-p1)*height[p1];
21                 p1++;
22             }
23             maxArea=area>maxArea?area:maxArea;
24         }
25         return maxArea;
26     }
27 };

 

【leetcode】Container With Most Water

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原文地址:http://www.cnblogs.com/reachteam/p/4199536.html

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