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Given an unsorted integer array, find the first missing positive integer.
For example,
Given [1,2,0]
return 3
,
and [3,4,-1,1]
return 2
.
Your algorithm should run in O(n) time and uses constant space.
1 class Solution { 2 public: 3 int firstMissingPositive(int A[], int n) { 4 5 if(n==0) return 1; 6 7 for(int i=0;i<n;i++) 8 { 9 if(A[i]!=i+1&&A[i]<=n&&A[i]>=1&&A[i]!=A[A[i]-1]) 10 { 11 swap(A[i],A[A[i]-1]); 12 i--; 13 } 14 } 15 16 for(int i=0;i<n;i++) 17 { 18 if(A[i]!=i+1) return i+1; 19 20 } 21 return n+1; 22 23 } 24 25 void swap(int &a,int &b) 26 { 27 int tmp=a; 28 a=b; 29 b=tmp; 30 } 31 };
【leetcode】First Missing Positive
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原文地址:http://www.cnblogs.com/reachteam/p/4199659.html