码迷,mamicode.com
首页 > 其他好文 > 详细

Twitter OA prepare: Anagram is A Palindrome

时间:2015-01-04 06:23:36      阅读:230      评论:0      收藏:0      [点我收藏+]

标签:

A string is a palindrome if it has exactly the same sequence of characters when traversed left-to-right as right-to-left. For example, the following strings are palindromes:

"kayak"

"codilitytilidoc"

"neveroddoreven"

A string A is an anagram of a string B if it consists of exactly the same characters, but possibly in another order. For example, the following strings are each other‘s anagrams:

A="mary" B="army" A="rocketboys" B="octobersky" A="codility" B="codility"

Write a function

int isAnagramOfPalindrome(String S);

which returns 1 if the string s is a anagram of some palindrome, or returns 0 otherwise.

For example your function should return 1 for the argument "dooernedeevrvn", because it is an anagram of a palindrome "neveroddoreven". For argument "aabcba", your function should return 0.

Algorithm:

  1. Count the number of occurrence of each character.

  2. Only one character with odd occurrence is allowed since in a palindrome maximum number of character with odd occurrence can be ‘1‘.

  3. All other character should occur in even number of times.

  4. If (2) and (3) fail, then the given string is not a palindrome.

 1 public int check(String str) {
 2     HashMap<Character, Integer> map = new HashMap<Character, Integer>();
 3     for (int i=0; i<str.length(); i++) {
 4         char c = str.charAt(i);
 5         if (map.containsKey(c)) {
 6             map.put(c, map.get(c)+1);
 7         }
 8         else {
 9             map.put(c, 1);
10         }
11     }
12   
13     int cntOdd = 0;
14     for (int val : map.values()) {
15         if (val % 2 == 1) {
16             cntOdd++;
17         }
18     }
19     return cntOdd>1? 0 : 1;
20 }

 

Twitter OA prepare: Anagram is A Palindrome

标签:

原文地址:http://www.cnblogs.com/EdwardLiu/p/4200259.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!