Suppose a sorted array is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7
might become 4
5 6 7 0 1 2
).
Find the minimum element.
You may assume no duplicate exists in the array.
二分法· 注意left和right的选择
public class Solution { public int findMin(int[] num) { assert num.length>0; int left = 0,right = num.length-1; while(left<right){ if(num[left]<num[right]) return num[left]; int mid = (left+right)/2; if(num[mid]>num[right]){ if(mid==left) left = mid++; left = mid; }else{ right = mid; } } return num[left]; } }
[LeetCode]Find Minimum in Rotated Sorted Array
原文地址:http://blog.csdn.net/guorudi/article/details/42395439