码迷,mamicode.com
首页 > 其他好文 > 详细

BZOJ3282 Tree

时间:2015-01-05 00:16:38      阅读:307      评论:0      收藏:0      [点我收藏+]

标签:

论什么是LCT?蒟蒻也不造。。。

splay写错是shen me gui = =

话说,要注意翻转标记!!!

还是要注意link & cut的写法啊喂!

 

技术分享
  1 /**************************************************************
  2     Problem: 3282
  3     User: rausen
  4     Language: C++
  5     Result: Accepted
  6     Time:1732 ms
  7     Memory:7840 kb
  8 ****************************************************************/
  9  
 10 #include <cstdio>
 11 #include <algorithm>
 12  
 13 using namespace std;
 14 const int N = 300005;
 15  
 16 struct splay_node {
 17   int v, res, rev;
 18   int fa, son[2];
 19 } tr[N];
 20  
 21 int n;
 22  
 23 inline int read() {
 24   int x = 0, sgn = 1;
 25   char ch = getchar();
 26   while (ch < 0 || 9 < ch) {
 27     if (ch == -) sgn = -1;
 28     ch = getchar();
 29   }
 30   while (0 <= ch && ch <= 9) {
 31     x = x * 10 + ch - 0;
 32     ch = getchar();
 33   }
 34   return sgn * x;
 35 }
 36  
 37 #define lson tr[p].son[0]
 38 #define rson tr[p].son[1]
 39 #define Rev tr[p].rev
 40 #define Res tr[p].res
 41 #define V tr[p].v
 42 #define Fa tr[p].fa
 43 inline void update(int p) {
 44   tr[0].res = 0;
 45   Res = tr[lson].res ^ tr[rson].res ^ V;
 46 }
 47  
 48 inline void push_down(int p) {
 49   if (p && Rev) {
 50     swap(lson, rson);
 51     tr[lson].rev ^= 1, tr[rson].rev ^= 1;
 52     Rev = 0;
 53   }
 54 }
 55  
 56 inline bool is_root(int p) {
 57   return Fa == 0 || (tr[Fa].son[0] != p && tr[Fa].son[1] != p);
 58 }
 59  
 60 inline void rotate(int p) {
 61   int fa = tr[p].fa, gr = tr[fa].fa;
 62   int l = (tr[fa].son[1] == p), r = !l;
 63   if (!is_root(fa)) tr[gr].son[tr[gr].son[1] == fa] = p;
 64   tr[p].fa = gr, tr[fa].fa = p, tr[tr[p].son[r]].fa = fa;
 65   tr[fa].son[l] = tr[p].son[r], tr[p].son[r] = fa;
 66   update(fa), update(p);
 67 }
 68  
 69 void splay(int p) {
 70   int fa, gr;
 71   while (!is_root(p)) {
 72     fa = tr[p].fa, gr = tr[fa].fa;
 73     push_down(gr), push_down(fa), push_down(p);
 74     if (!is_root(fa))
 75       if ((fa == tr[gr].son[0]) ^ (p == tr[fa].son[0])) rotate(p);
 76       else rotate(fa);
 77     rotate(p);
 78   }
 79   push_down(p);
 80 }
 81  
 82  
 83 void access(int p) {
 84   int t;
 85   for (t = 0; p; t = p, p = Fa) {
 86     splay(p);
 87     rson = t, update(p);
 88   }
 89 }
 90  
 91 void make_root(int p) {
 92   access(p), splay(p);
 93   Rev ^= 1;
 94 }
 95  
 96 int find_root(int p) {
 97   access(p), splay(p);
 98   while (lson) {
 99     push_down(p);
100     p = lson;
101   }
102   return p;
103 }
104  
105  
106 void cut(int x, int y) {
107   make_root(x);
108   access(y), splay(y);
109   if (tr[y].son[0] == x && tr[x].son[1] == 0)
110     tr[y].son[0] = tr[x].fa = 0, update(y);
111 }
112  
113 void link(int x, int y) {
114   make_root(x);
115   tr[x].fa = y;
116 }
117  
118 int main() {
119   int i, Q, oper, x, y;
120   n = read(), Q = read();
121   for (i = 1; i <= n; ++i)
122     tr[i].v = tr[i].res = read();
123   while (Q--) {
124     oper = read(), x = read(), y = read();
125     if (oper == 0) {
126       make_root(x);
127       access(y), splay(y);
128       printf("%d\n", tr[y].res);
129     } else if (oper == 1) {
130       if (find_root(x) != find_root(y)) link(x, y);
131     }
132     else if (oper == 2) {
133       if (find_root(x) == find_root(y)) cut(x, y);
134     }
135     else {
136       access(x), splay(x);
137       tr[x].v = y;
138       update(x);
139     }
140   }
141   return 0;
142 }
View Code

(p.s.  不要问为什么窝改了代码风格。。。)

BZOJ3282 Tree

标签:

原文地址:http://www.cnblogs.com/rausen/p/4202440.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!