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[LeetCode] Find Minimum in Rotated Sorted Array 二分搜索

时间:2015-01-06 15:15:40      阅读:111      评论:0      收藏:0      [点我收藏+]

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Suppose a sorted array is rotated at some pivot unknown to you beforehand.

(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).

Find the minimum element.

You may assume no duplicate exists in the array.

 

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 Array Binary Search
 

  二分查找的变形,比较神奇的是数列可能没有旋转,查找前判断下数列旋转了没有便可以应对。
 
技术分享
#include <iostream>
#include <vector>
using namespace std;

class Solution {
public:
    int findMin(vector<int> &num) {
        int n = num.size();
        if(n<2||num[0]<num[n-1]) return num[0];
        int lft=0,rgt=n-1,mid=n-1;
        while(lft+1<rgt){
            if(num[mid-1]>num[mid]) break;
            mid = (lft+ rgt)/2;
            cout<<lft<<" "<<mid<<" "<<rgt<<endl;
            if(num[lft]<num[mid])   lft=mid;
            else    rgt=mid;
            mid = rgt;
        }
        return num[mid];
    }
};

int main()
{
    vector<int> num{3,4,5,6,1,2};
    Solution sol;
    cout<<sol.findMin(num)<<endl;
    return 0;
}
View Code

 

[LeetCode] Find Minimum in Rotated Sorted Array 二分搜索

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原文地址:http://www.cnblogs.com/Azhu/p/4205914.html

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