标签:
Suppose a sorted array is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7
might become 4 5 6 7 0 1 2
).
Find the minimum element.
You may assume no duplicate exists in the array.
Array Binary Search
#include <iostream> #include <vector> using namespace std; class Solution { public: int findMin(vector<int> &num) { int n = num.size(); if(n<2||num[0]<num[n-1]) return num[0]; int lft=0,rgt=n-1,mid=n-1; while(lft+1<rgt){ if(num[mid-1]>num[mid]) break; mid = (lft+ rgt)/2; cout<<lft<<" "<<mid<<" "<<rgt<<endl; if(num[lft]<num[mid]) lft=mid; else rgt=mid; mid = rgt; } return num[mid]; } }; int main() { vector<int> num{3,4,5,6,1,2}; Solution sol; cout<<sol.findMin(num)<<endl; return 0; }
[LeetCode] Find Minimum in Rotated Sorted Array 二分搜索
标签:
原文地址:http://www.cnblogs.com/Azhu/p/4205914.html