The string "PAYPALISHIRING"
is written in a zigzag pattern on a given number of rows like
this: (you may want to display this pattern in a fixed font for better legibility)
P A H N A P L S I I G Y I RAnd then read line by line:
"PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string text, int nRows);
convert("PAYPALISHIRING", 3)
should
return "PAHNAPLSIIGYIR"
.
解决方法:将原字符串先向下后向上依次填入字符串数组,然后将所有的字符串相加即可得到输出。
class Solution { public: string convert(string s, int nRows) { if(nRows == 1) return s; string temp[nRows]; for(int i=0; i<nRows; i++) temp[i] = ""; bool down = true; int j=0; for(int i=0; i<s.length(); i++) { temp[j] = temp[j] + s[i]; if(j == nRows-1) down = false; else if(j == 0) down = true; if(down) j++; else j--; } string res=""; for(int i=0; i<nRows; i++) res +=temp[i]; return res; } };
原文地址:http://blog.csdn.net/shaya118/article/details/42506371