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Find the contiguous subarray within an array (containing at least one number) which has the largest product.
For example, given the array [2,3,-2,4],
the contiguous subarray [2,3] has the largest product = 6.
class Solution { public: int maxProduct(int A[], int n) { int res = A[0]; int tmp_max = A[0], tmp_min = A[0]; for (int i = 1; i < n; ++i) { int cpy_max = tmp_max; tmp_max = max(max(tmp_max * A[i], A[i]), tmp_min * A[i]); tmp_min = min(min(cpy_max * A[i], A[i]), tmp_min * A[i]); res = max(res, tmp_max); } return res; } };
有一点要注意。每次循环要备份一下tmp_max，因为经过了对tmp_max的操作，tmp_max的值已经改变了，所以要使用cpy_max来保存改变之前的tmp_max的值。
[LeetCode] Maximum Product Subarray
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原文地址：http://www.cnblogs.com/easonliu/p/4210408.html
