LeetCode--Container With Most Water

标签：leetcode   容器   面试题   

Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

Note: You may not slant the container.

解题思路：影响蓄水量的因素包括容器的宽度以及容器的最短的挡板的高度，因此我们可以先将容器的宽度设为最大宽度，如此即可得到此时的最大值，为了让容器的体积增大，只有将最短的边变高才可能在容器宽度减小的情况下增大容器的容量。因此即可得到如下的代码

class Solution 
{
public:
    int maxArea(vector<int> &height) 
    {
        int n = height.size();
        if(n<=1)
            return 0;
        vector<int> h = height;
        int start=0;
        int end = n-1;
        int res = 0;
        while(start<end)
        {
            int temp = end - start;
            if(h[start] > h[end])
            {
                temp = temp*h[end];
                end--;
            }
            else 
            {
                temp = temp*h[start];
                start++;
            }
            if(temp > res)
                res = temp;
        }
        return res;
    }
};

LeetCode--Container With Most Water

标签：leetcode   容器   面试题   

原文地址：http://blog.csdn.net/shaya118/article/details/42531065