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LintCode-Minimum Path Sum

时间:2015-01-09 09:10:42      阅读:176      评论:0      收藏:0      [点我收藏+]

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Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.

Note You can only move either down or right at any point in time.

Solution:

 

 1 public class Solution {
 2     /**
 3      * @param grid: a list of lists of integers.
 4      * @return: An integer, minimizes the sum of all numbers along its path
 5      */
 6     public int minPathSum(int[][] grid) {
 7         int rowNum = grid.length;
 8         if (rowNum==0) return 0;
 9         int colNum = grid[0].length;
10         if (colNum==0) return 0;
11         
12         int[][] sum = new int[rowNum][colNum];
13         sum[0][0] = grid[0][0];
14         for (int i=1;i<rowNum;i++) sum[i][0] = sum[i-1][0]+grid[i][0];
15         for (int i=1;i<colNum;i++) sum[0][i] = sum[0][i-1]+grid[0][i];
16         
17         for (int i=1;i<rowNum;i++)
18             for (int j=1;j<colNum;j++){
19                 sum[i][j] = Math.min(sum[i-1][j],sum[i][j-1])+grid[i][j];
20             }
21                 
22         return sum[rowNum-1][colNum-1];
23     }
24 }

 

LintCode-Minimum Path Sum

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原文地址:http://www.cnblogs.com/lishiblog/p/4212421.html

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