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Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.
1 /** 2 * Definition for singly-linked list. 3 * struct ListNode { 4 * int val; 5 * ListNode *next; 6 * ListNode(int x) : val(x), next(NULL) {} 7 * }; 8 */ 9 /** 10 * Definition for binary tree 11 * struct TreeNode { 12 * int val; 13 * TreeNode *left; 14 * TreeNode *right; 15 * TreeNode(int x) : val(x), left(NULL), right(NULL) {} 16 * }; 17 */ 18 class Solution { 19 public: 20 TreeNode *sortedListToBST(ListNode *head) { 21 22 ListNode *p=head; 23 int len=0; 24 while(p!=NULL) 25 { 26 p=p->next; 27 len++; 28 } 29 30 TreeNode * root=buildTree(head,0,len-1); 31 return root; 32 33 } 34 35 36 TreeNode *buildTree(ListNode *&node,int left,int right) 37 { 38 if(left>right) return NULL; 39 40 int mid=(left+right)/2; 41 42 TreeNode *leftTree=buildTree(node,left,mid-1); 43 TreeNode *root=new TreeNode(node->val); 44 node=node->next; 45 TreeNode *rightTree=buildTree(node,mid+1,right); 46 root->left=leftTree; 47 root->right=rightTree; 48 return root; 49 } 50 51 };
【leetcode】Convert Sorted List to Binary Search Tree
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原文地址:http://www.cnblogs.com/reachteam/p/4216420.html