Date
--------
14/05/24
Date
--------
14/05/24
SET SESSION DATEFORM=ANSIDATE; /*ANSI default format (YYYY-MM-DD) */
SET SESSION DATEFORM=INTEGERDATE; /*Teradata default format (YY/MM/DD) */
| |
INTERVAL
-‘32‘ YEAR (-32 years) [Must
use explicit -]
INTERVAL ‘9‘ MONTH
(+9 months) [The default is +]
INTERVAL ‘5-08‘ YEAR TO
MONTH (+5 years, 8 months) [You can‘t use explicit
+]
INTERVAL
- ‘365‘ DAY (-365 days)
SELECT DATE + INTERVAL - ‘32‘ YEAR ;
(Date+-32)
----------
82/05/24
SELECT DATE + INTERVAL ‘5-08‘ YEAR TO MONTH;
(Date+
5-08)
------------
20/01/24
Date
Literals
|
Date
literals must always be represented using the ANSI standard date
format, regardless of the DATEFORM being
used by the session.
The ANSI
standard Date format is: DATE
‘YYYY-MM-DD‘
You may
add the DATE literal
to the to any of the following intervals:
| |
DATE(literal)
+/- YEAR / YEAR TO MONTH / MONTH / DAY
SELECT DATE ‘2014-05-24‘ + INTERVAL ‘2-05‘ YEAR TO MONTH ;
(2014-05-24+
2-05)
------------------
16/10/24
SELECT ADD_MONTHS (DATE ‘2005-12-29‘,2 );
ADD_MONTHS(2005-12-29,
2)
-------------------------
2006-02-28
SELECT ADD_MONTHS (DATE ‘2003-12-31‘, 2 );
Date Subtraction Yields
Days
SELECT DATE ‘2007-03-01‘ - DATE ‘2004-01-01‘ ;
(2007-03-01-2004-01-01)
-----------------------
1155
SELECT (DATE ‘2007-03-01‘ - DATE ‘2004-01-01‘ ) DAY;
*** Failure 7453 INTERVAL field overflow.
This is because the default field length for day is 2 digits and
1155 is 4 digits. In the next example, we submit the query with the output
defined as DAY(4)which generates the correct answer.
SELECT (DATE ‘2007-03-01‘ - DATE ‘2004-01-01‘ ) DAY(4);
(2007-03-01
- 2004-01-01)
DAY
-----------------------------
1155
SELECT (DATE ‘1999-03-01‘ - DATE ‘1899-01-01‘ ) YEAR TO MONTH ;
*** Failure 7453 INTERVAL field overflow.
SELECT (DATE ‘1999-03-01‘ - DATE ‘1899-01-01‘ ) YEAR(3) TO MONTH;
(1999-03-01
- 1899-01-01) YEAR TO
MONTH
---------------------------------------
100-02
SELECT CAST ((DATE‘2004-03-01‘ - DATE‘2004-01-01‘ ) AS INTERVAL MONTH);
(2004-03-01-2004-01-01)
-----------------------
60
SELECT CAST ((INTERVAL ‘3-04‘ YEAR TO MONTH) AS INTERVAL MONTH);
3-04
-----
40
Extracting From
Date
SELECT EXTRACT (YEAR FROM DATE ‘2004-12-15‘)
SELECT EXTRACT (YEAR FROM (DATE ‘2004-12-15‘ + INTERVAL ‘20‘ DAY)) ;
SELECT EXTRACT (MONTH FROM (DATE ‘2004-12-15‘ + INTERVAL ‘20‘ DAY));
SELECT EXTRACT (DAY FROM (DATE ‘2004-12-15‘ + INTERVAL ‘20‘ DAY)) ;
SELECT INTERVAL ‘03
05:23‘ DAY TO MINUTE + INTERVAL ‘02
03:23‘ DAY TO MINUTE ;
SELECT CAST ((TIME ‘09:30:22‘ - INTERVAL ‘01:20:10.45‘ HOUR TO SECOND) AS TIME( 2));
SELECT TIME ‘09:30:22‘ + INTERVAL ‘01:20‘ HOUR TO MINUTE ;
SELECT (TIME ‘10:35:40‘- TIME ‘08:00:00‘ ) HOUR;
SELECT CAST ((INTERVAL ‘3:45‘ HOUR TO MINUTE) AS INTERVAL HOUR);
