Given a list, rotate the list to the right by k places, where k is non-negative.
For example:
Given 1->2->3->4->5->NULL
and k = 2
,
return 4->5->1->2->3->NULL
.
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode *rotateRight(ListNode *head, int k) { if(head == NULL) return head; ListNode* temp = head; int count = 0; while(temp != NULL) { count++; temp = temp->next; } k = k%count; if(k == 0) return head; ListNode* pre = head; ListNode* end = head; int i=1; while(i<k && end->next!=NULL) { end = end->next; i++; } if(i != k) return head; else { ListNode* temp; while(end->next!=NULL) { temp = pre; pre = pre->next; end = end->next; } temp->next = end->next; end->next = head; return pre; } } };
原文地址:http://blog.csdn.net/shaya118/article/details/42642055