Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.
For example,
Given 1->2->3->3->4->4->5
, return 1->2->5
.
Given 1->1->1->2->3
, return 2->3
.
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode *deleteDuplicates(ListNode *head) { if(head==NULL || head->next==NULL) return head; ListNode* save = head; int flag = head->next->val; ListNode* pre = head->next; ListNode* end = pre->next; while(end != NULL) { if(pre->val != end->val) { if(pre->next == end) { save = pre; pre = end; } else { save->next = end; pre = end; } } end = end->next; } if(pre->next != NULL) save->next = NULL; while(head!=NULL && head->next!=NULL) { if(head->val!=head->next->val) break; head = head->next; } if(head!=NULL && head->val == flag) head = head->next; return head; } };
LeetCode--Remove Duplicates from Sorted List II
原文地址:http://blog.csdn.net/shaya118/article/details/42677161