LeetCode--Binary Tree Inorder Traversal

标签：tree   traversal   leetcode   

Given a binary tree, return the inorder traversal of its nodes‘ values.

For example:
Given binary tree {1,#,2,3},

   1
         2
    /
   3

return [1,3,2].

Note: Recursive solution is trivial, could you do it iteratively?

confused what "{1,#,2,3}" means? > read more on how binary tree is serialized on OJ.

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution 
{
public:
    vector<int> inorderTraversal(TreeNode *root) 
	{
        vector<int> res;
		get_res(root,res);
		return res;
    }
	void get_res(TreeNode* x,vector<int>& res)
	{
		if(x == NULL)
			return;
		get_res(x->left,res);
		res.push_back(x->val);
		get_res(x->right,res);
	}
};

LeetCode--Binary Tree Inorder Traversal

标签：tree   traversal   leetcode   

原文地址：http://blog.csdn.net/shaya118/article/details/42680603