标签:leetcode traversal 中序遍历 深度优先搜索
Given two binary trees, write a function to check if they are equal or not.
Two binary trees are considered equal if they are structurally identical and the nodes have the same value.
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: bool isSameTree(TreeNode *p, TreeNode *q) { if(p==NULL && q==NULL) return true; if(q==NULL || p == NULL) return false; if(p->val != q->val) return false; bool left = isSameTree(p->left,q->left); bool right = isSameTree(p->right,q->right); return left&&right; } };
标签:leetcode traversal 中序遍历 深度优先搜索
原文地址:http://blog.csdn.net/shaya118/article/details/42705393