标签:leetcode bst tree 递归 深度优先搜索
Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: bool isBalanced(TreeNode *root) { if(root == NULL) return true; int l = height(root->left); int r = height(root->right); if(abs(l-r)>1) return false; bool left = isBalanced(root->left); bool right = isBalanced(root->right); return left&&right; } int height(TreeNode* root) { if(root == NULL) return 0; int l = height(root->left); int r = height(root->right); return l>r? (l+1):(r+1); } };
LeetCode--Balanced Binary Tree
标签:leetcode bst tree 递归 深度优先搜索
原文地址:http://blog.csdn.net/shaya118/article/details/42710377