码迷,mamicode.com
首页 > 其他好文 > 详细

LeetCode--Populating Next Right Pointers in Each Node

时间:2015-01-14 18:00:03      阅读:139      评论:0      收藏:0      [点我收藏+]

标签:leetcode   tree   递归   traversal   层次遍历   

Given a binary tree

    struct TreeLinkNode {
      TreeLinkNode *left;
      TreeLinkNode *right;
      TreeLinkNode *next;
    }

Populate each next pointer to point to its next right node. If there is no next right node, the next pointer should be set to NULL.

Initially, all next pointers are set to NULL.

Note:

  • You may only use constant extra space.
  • You may assume that it is a perfect binary tree (ie, all leaves are at the same level, and every parent has two children).

For example,
Given the following perfect binary tree,

         1
       /        2    3
     / \  /     4  5  6  7

After calling your function, the tree should look like:

         1 -> NULL
       /        2 -> 3 -> NULL
     / \  /     4->5->6->7 -> NULL

/**
 * Definition for binary tree with next pointer.
 * struct TreeLinkNode {
 *  int val;
 *  TreeLinkNode *left, *right, *next;
 *  TreeLinkNode(int x) : val(x), left(NULL), right(NULL), next(NULL) {}
 * };
 */
class Solution 
{
public:
    void connect(TreeLinkNode *root) 
    {
        if(root == NULL)
            return ;
        TreeLinkNode* temp = root;
        while(temp->left!=NULL)
        {
            TreeLinkNode* t = temp;
            while(t!=NULL)
            {
                t->left->next = t->right;
                if(t->next != NULL)
                    t->right->next = t->next->left;
                t = t->next;
            }
            temp = temp->left;
        }
        return ;
    }
};


LeetCode--Populating Next Right Pointers in Each Node

标签:leetcode   tree   递归   traversal   层次遍历   

原文地址:http://blog.csdn.net/shaya118/article/details/42712415

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!