标签:leetcode
Given an index k, return the kth row of the Pascal‘s triangle.
For example, given k = 3,
Return [1,3,3,1].
Note:
Could you optimize your algorithm to use only O(k) extra space?
class Solution
{
public:
vector<int> getRow(int rowIndex)
{
vector<int> pre;
vector<int> res;
res.push_back(1);
for(int i=1; i<=rowIndex; i++)
{
pre = res;
res.clear();
res.push_back(1);
for(int j=1; j<pre.size(); j++)
res.push_back(pre[j]+pre[j-1]);
res.push_back(1);
}
return res;
}
};LeetCode--Pascal's Triangle II
标签:leetcode
原文地址:http://blog.csdn.net/shaya118/article/details/42716681