标签:leetcode
Given an index k, return the kth row of the Pascal‘s triangle.
For example, given k = 3,
Return [1,3,3,1]
.
Note:
Could you optimize your algorithm to use only O(k) extra space?
class Solution { public: vector<int> getRow(int rowIndex) { vector<int> pre; vector<int> res; res.push_back(1); for(int i=1; i<=rowIndex; i++) { pre = res; res.clear(); res.push_back(1); for(int j=1; j<pre.size(); j++) res.push_back(pre[j]+pre[j-1]); res.push_back(1); } return res; } };
LeetCode--Pascal's Triangle II
标签:leetcode
原文地址:http://blog.csdn.net/shaya118/article/details/42716681