LeetCode--Best Time to Buy and Sell Stock

标签：leetcode   动态规划   

Say you have an array for which the ith element is the price of a given stock on day i.

If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit.

class Solution 
{
public:
    int maxProfit(vector<int> &prices) 
	{
		vector<int>& p = prices;
		int n = p.size();
		if(n==0 || n==1)
			return 0;
		int max = 0;
		int temp = 0;
		int min = p[0];
		for(int i=1; i<n; i++)
		{
			if(p[i] > min && temp < p[i]-min)
			{
				temp = p[i] - min;
			}
			else if(p[i] < min)
			{
				if(max > temp)
					max = temp;
				min = p[i];
			}
		}
		if(temp > max)
			max = temp;
		return max;
    }
};

LeetCode--Best Time to Buy and Sell Stock

标签：leetcode   动态规划   

原文地址：http://blog.csdn.net/shaya118/article/details/42719521