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Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 65535/32768 K (Java/Others)
Total Submission(s): 2186 Accepted Submission(s): 696
1 #include <stdio.h> 2 #include <string.h> 3 #include <algorithm> 4 using namespace std; 5 6 int n,a[205],b[205],dp[205]; 7 8 int LICS() 9 { 10 int MAX,i,j,k; 11 memset(dp,0,sizeof(dp)); 12 MAX = 0; 13 for(i = 1; i<=n; i++) 14 { 15 k = 0; 16 for(j = 1; j<=n-i+1; j++) 17 { 18 if(a[i] == b[j]) 19 { 20 if(j!=(n-i+1))//没与自身匹配 21 { 22 if(dp[j]<(dp[k]+2))//长度加2 23 dp[j] = dp[k]+2; 24 } 25 else//与自身匹配了 26 { 27 if(dp[j]<(dp[k]+1))//自身所以只加1长度 28 dp[j] = dp[k]+1; 29 } 30 } 31 else if(a[i]>b[j] && dp[k]<dp[j]) 32 k = j; 33 if(MAX<dp[j]) 34 MAX = dp[j]; 35 } 36 } 37 38 return MAX; 39 } 40 41 int main() 42 { 43 int t,i; 44 scanf("%d",&t); 45 while(t--) 46 { 47 scanf("%d",&n); 48 for(i = 1; i<=n; i++) 49 scanf("%d",&a[i]); 50 for(i = 1; i<=n; i++) 51 b[i] = a[n-i+1]; 52 printf("%d\n",LICS()); 53 } 54 55 return 0; 56 }
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原文地址:http://www.cnblogs.com/caterpillarofharvard/p/4226482.html