标签：des style class blog c code
Problem Description
In your childhood, do you crazy for collecting the
beautiful cards in the snacks? They said that, for example, if you collect all
the 108 people in the famous novel Water Margin, you will win an amazing
award.
As a smart boy, you notice that to win the award, you must
buy much more snacks than it seems to be. To convince your friends not to waste
money any more, you should find the expected number of snacks one should buy to
collect a full suit of cards.
Input
The first line of each test case contains one integer
N (1 <= N <= 20), indicating the number of different cards you need the
collect. The second line contains N numbers p1, p2, ..., pN, (p1 + p2 + ... + pN
<= 1), indicating the possibility of each card to appear in a bag of
snacks.
Note there is at most one card in a bag of snacks. And it
is possible that there is nothing in the bag.
Output
Output one number for each test case, indicating the
expected number of bags to buy to collect all the N different cards.
You
will get accepted if the difference between your answer and the standard answer
is no more that 10^-4.
Sample Input
Sample Output
10.000
10.500
题目大意： 给出N个奖品，每买一个物品得到第i个奖品的概率为ai，求收集齐所有的奖品需要买多少物品的数学期望。
思路：简单第容斥原来。用i表示取奖品第状态，按个数判断加或减
1 #include<cstdio>
2
3 int main()
4 {
5 int n;
6 double a[21];
7 while (~scanf("%d",&n))
8 {
9 for (int i=0;i<n;++i)
10 scanf("%lf",&a[i]);
11 double temp,ans=0;
12 for (int i=1;i< (1<<n);++i)
13 {
14 temp=0;
15 int ct=0;
16 for (int j=0;j<n;++j)
17 if (i & (1<<(j) ) )
18 {
19 ct++;
20 temp+=a[j];
21 }
22 if (ct & 1) ans+=1/temp;
23 else ans-=1/temp;
24 }
25 printf("%.4f\n",ans);
26 }
27 return 0;
28 }
hdu4336 Card Collector,布布扣,bubuko.com
hdu4336 Card Collector
标签：des style class blog c code
原文地址：http://www.cnblogs.com/code-painter/p/3751054.html
