Maximum Gap

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Given an unsorted array, find the maximum difference between the successive elements in its sorted form.

Try to solve it in linear time/space.

Return 0 if the array contains less than 2 elements.

You may assume all elements in the array are non-negative integers and fit in the 32-bit signed integer range.

解法1： 时间O(nlogn), 空间O(1). 排序在比较。

 1 public class Solution {
 2     public int maximumGap(int[] num) {
 3         if(num == null || num.length < 2) return 0;
 4         Arrays.sort(num);
 5         int result = 0;
 6         for(int i = 0; i < num.length - 1; i ++){
 7             result = Math.max(result, num[i + 1] - num[i]);
 8         }
 9         return result;
10     }
11 }

Maximum Gap

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原文地址：http://www.cnblogs.com/reynold-lei/p/4229146.html