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Given a collection of intervals, merge all overlapping intervals.
For example,
Given [1,3],[2,6],[8,10],[15,18]
,
return [1,6],[8,10],[15,18]
.
1 /** 2 * Definition for an interval. 3 * public class Interval { 4 * int start; 5 * int end; 6 * Interval() { start = 0; end = 0; } 7 * Interval(int s, int e) { start = s; end = e; } 8 * } 9 */ 10 class intervalComparator implements Comparator<Interval>{ 11 @Override 12 public int compare(Interval o1, Interval o2) { 13 return o1.start-o2.start; 14 } 15 } 16 public class Solution { 17 public List<Interval> merge(List<Interval> intervals) { 18 List<Interval> result = new ArrayList<Interval>(); 19 if (intervals.size() == 0) { 20 return result; 21 } 22 Collections.sort(intervals, new intervalComparator()); 23 Interval first = intervals.get(0); 24 Interval next; 25 for (int i = 1; i <intervals.size() ; i++) { 26 next = intervals.get(i); 27 if (first.end < next.start) { 28 result.add(first); 29 first = next; 30 } else { 31 if (first.end < next.end) { 32 first.end = next.end; 33 } 34 } 35 } 36 result.add(first); 37 return result; 38 } 39 }
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原文地址:http://www.cnblogs.com/birdhack/p/4229898.html