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1033The cost of this solution is 6 pounds. Note that the digit 1 which got pasted over in step 2 can not be reused in the last step – a new 1 must be purchased.
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#include<iostream> #include<cstring> #include<queue> using namespace std; bool rem[10005]; int rans[10005]; void getPrime() { for(int i=2;i<10000;++i) if(rem[i]==0) for(int j=i*2;j<10000;j+=i) rem[j]=1; } int bfs(int S,int E) { memset(rans,-1,sizeof(rans)); queue<int> que; int t; int temp; que.push(S); rans[S]=0; while(!que.empty()) { t=que.front(); que.pop(); if(t==E) return rans[E]; for(int i=1;i<=9;++i) { temp=t%1000+i*1000; if(rans[temp]==-1&&rem[temp]==0) { rans[temp]=rans[t]+1; que.push(temp); } } for(int i=0;i<=9;++i) { temp=t%100+100*i+(t/1000)*1000; if(rans[temp]==-1&&rem[temp]==0) { rans[temp]=rans[t]+1; que.push(temp); } } for(int i=0;i<=9;++i) { temp=t%10+10*i+(t/100)*100; if(rans[temp]==-1&&rem[temp]==0) { rans[temp]=rans[t]+1; que.push(temp); } } for(int i=0;i<=9;++i) { temp=(t/10)*10+i; if(rans[temp]==-1&&rem[temp]==0) { rans[temp]=rans[t]+1; que.push(temp); } } } return -1; } int main() { ios::sync_with_stdio(false); getPrime(); int T; int a,b; int ans; cin>>T; while(T--) { cin>>a>>b; ans=bfs(a,b); if(ans==-1) cout<<"Impossible\n"; else cout<<ans<<endl; } return 0; }
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原文地址:http://www.cnblogs.com/whywhy/p/4229881.html