int MaxSub(int *a, int n) { int sum = 0; int tmp; for (int i = 0; i < n; i++) { for (int j = i; j < n; j++) { tmp = 0; for (int k = i; k <= j; k++) tmp += a[k]; if (tmp > sum) sum = tmp; } } return sum; }
int MaxSub(int *a, int n) { int sum = 0; int tmp = 0; for (int i = 0; i < n; i++) { for (int j = i; j < n; j++) { tmp += a[j]; if (tmp > sum) sum = tmp; } tmp = 0; } return sum; }
int MaxSub(int *a, int left, int right) { // 这里的基准情况是关键 if (left == right) { if (a[left] > 0) return a[left]; else return 0; } int middle = (left+right)/2; int leftmax = MaxSub(a, left, middle); int rightmax = MaxSub(a, middle+1, right); int tmp = 0; int leftbordersum = 0; for (int i = middle; i >= left; i--) { tmp += a[i]; if (tmp > leftbordersum) leftbordersum = tmp; } tmp = 0; int rightbordersum = 0; for (int i = middle+1; i <= right; i++) { tmp += a[i]; if (tmp > rightbordersum) rightbordersum = tmp; } int bordersum = leftbordersum + rightbordersum; return max3(leftmax, rightmax, bordersum); }
int MaxSub(int *a, int n) { int tmp = 0; int sum = 0; for (int i = 0; i < n; i++) { tmp += a[i]; if (tmp > sum) sum = tmp; else if (tmp < 0) tmp = 0; } return sum; }
原文地址:http://blog.csdn.net/nestler/article/details/26966925