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Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 65535/32768 K (Java/Others)
Total Submission(s): 2759 Accepted Submission(s): 1420
#include<iostream> #include<cstdio> #include<cmath> #include<cstdlib> #include<string> #include<algorithm> #include<cstring> using namespace std; int a[110],b[110],dp[100010]; int n,m; int main() { while(scanf("%d",&n)!=EOF) { memset(dp,0,sizeof(dp)); for(int i=1;i<=n;i++) scanf("%d%d",&a[i],&b[i]); scanf("%d",&m); for(int i=1;i<=n;i++) { for(int j=b[i];j<=m;j++) dp[j]=max(dp[j],dp[j-b[i]]+a[i]); } printf("%d\n",dp[m]); } return 0; }
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原文地址:http://www.cnblogs.com/a972290869/p/4231274.html