LeetCode Container With Most Water

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Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

Note: You may not slant the container.

题意：x轴上的n条垂直线，求类似木板盛水的最大值

思路：双指针加贪心，每次对当前的l和r围成的水池计算面积，然后对于更新l或r的话，就看curL和curR的大小，贪心的来看的话，如果curL<curR的话，那么将l指针向右移动显然是比较好的，移动到的位置取决于是否能找到更大的curL，至于另外一种情况类似

class Solution {
public:
    int maxArea(vector<int> &height) {
        int l, r;
        int len = height.size() - 1;
        l = 0, r = len;
        int curL = height[l];
        int curR = height[r];
        int Max = 0;

        while (l < r) {
            int tmp = min(curL, curR) * (r - l); 
            if (Max < tmp) Max = tmp;
            if (curL > curR) {
                while(l < r && curR >= height[r]) r--;
                if (l < r) curR = height[r];
            } else {
                while (l < r && curL >= height[l]) l++;
                if (l < r) curL = height[l];
            }
        }

        return Max;
    }
};

LeetCode Container With Most Water

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原文地址：http://blog.csdn.net/u011345136/article/details/42815387