标签：des style c class blog code
| Time Limit: 1000MS | Memory Limit: 65536K | |
| Total Submissions: 13523 | Accepted: 9407 |
Description
A checksum is an algorithm that scans a packet of data and returns a single number. The idea is that if the packet is changed, the checksum will also change, so checksums are often used for detecting transmission errors, validating document contents, and in many other situations where it is necessary to detect undesirable changes in data.
For this problem, you will implement a checksum algorithm called Quicksum. A Quicksum packet allows only uppercase letters and spaces. It always begins and ends with an uppercase letter. Otherwise, spaces and letters can occur in any combination, including consecutive spaces.
A Quicksum is the sum of the products of each character‘s position in the
packet times the character‘s value. A space has a value of zero, while letters
have a value equal to their position in the alphabet. So, A=1, B=2, etc.,
through Z=26. Here are example Quicksum calculations for the packets
"ACM" and "MID CENTRAL":
ACM: 1*1 + 2*3 + 3*13 = 46
MID CENTRAL: 1*13 + 2*9 + 3*4 + 4*0 + 5*3 + 6*5 + 7*14 + 8*20 + 9*18 + 10*1 + 11*12 = 650
Input
The input consists of one or more packets followed by a line containing only # that signals the end of the input. Each packet is on a line by itself, does not begin or end with a space, and contains from 1 to 255 characters.
Output
For each packet, output its Quicksum on a separate line in the output.
Sample Input
ACM MID CENTRAL REGIONAL PROGRAMMING CONTEST ACN A C M ABC BBC #
Sample Output
46 650 4690 49 75 14 15
Source
1 #include <iostream> 2 #include <cstring> 3 #include<cstdio> 4 using namespace std; 5 6 int main() 7 { 8 char str[256]; 9 char rule[27]={‘A‘,‘B‘,‘C‘,‘D‘,‘E‘,‘F‘,‘G‘,‘H‘,‘I‘,‘J‘,‘K‘,‘L‘,‘M‘, 10 ‘N‘,‘O‘,‘P‘,‘Q‘,‘R‘,‘S‘,‘T‘,‘U‘,‘V‘,‘W‘,‘X‘,‘Y‘,‘Z‘}; 11 while(gets(str)) 12 { 13 if(str[0]==‘#‘) 14 break; 15 int len = strlen(str); 16 int sum = 0; 17 for(int i = 0;i<len;i++) 18 { 19 if(str[i]==‘ ‘) 20 continue; 21 for(int j = 0;j<26;j++) 22 { 23 if(str[i]==rule[j]) 24 { 25 sum =sum +(i+1)*(j+1); 26 break; 27 } 28 } 29 } 30 cout<<sum<<endl; 31 } 32 return 0; 33 }
标签：des style c class blog code
原文地址：http://www.cnblogs.com/jhldreams/p/3751910.html
