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题目:给你一个后缀表达式,展开成二叉树,然后从深层向根的方向输出树上的字符。
分析:DS,递归,搜索。利用递归建树,然后bfs,逆序输出即可。
说明:目标550题!
#include <algorithm>
#include <iostream>
#include <cstdlib>
#include <cstring>
#include <cstdio>
#include <cmath>
using namespace std;
char Str[10001];
typedef struct tnode
{
char V;
tnode *L;
tnode *R;
}tnode;
tnode Node[10001];
int TreeSize,Now;
tnode* madetree()
{
int id = TreeSize ++;
Node[id].V = Str[-- Now];
if (Node[id].V <= 'Z') {
Node[id].R = madetree();
Node[id].L = madetree();
}
return &Node[id];
}
tnode* Q[10001];
char output[10001];
void bfs(tnode *root)
{
int move = 0,save = 0,count = 0;
Q[save ++] = root;
while (move < save) {
tnode* now = Q[move ++];
output[count ++] = now->V;
if (now->L) Q[save ++] = now->L;
if (now->R) Q[save ++] = now->R;
}
while (count)
printf("%c",output[-- count]);
printf("\n");
}
int main()
{
int t;
while (~scanf("%d",&t))
while (t --) {
scanf("%s",Str);
TreeSize = 0;
memset(Node, 0, sizeof(Node));
Now = strlen(Str);
bfs(madetree());
}
return 0;
}
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原文地址:http://blog.csdn.net/mobius_strip/article/details/43020769