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贪心 --- 巧妙解法

时间:2014-05-28 00:52:09      阅读:239      评论:0      收藏:0      [点我收藏+]

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Moving Tables

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 18319    Accepted Submission(s): 6268


Problem Description
The famous ACM (Advanced Computer Maker) Company has rented a floor of a building whose shape is in the following figure.

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The floor has 200 rooms each on the north side and south side along the corridor. Recently the Company made a plan to reform its system. The reform includes moving a lot of tables between rooms. Because the corridor is narrow and all the tables are big, only one table can pass through the corridor. Some plan is needed to make the moving efficient. The manager figured out the following plan: Moving a table from a room to another room can be done within 10 minutes. When moving a table from room i to room j, the part of the corridor between the front of room i and the front of room j is used. So, during each 10 minutes, several moving between two rooms not sharing the same part of the corridor will be done simultaneously. To make it clear the manager illustrated the possible cases and impossible cases of simultaneous moving.

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For each room, at most one table will be either moved in or moved out. Now, the manager seeks out a method to minimize the time to move all the tables. Your job is to write a program to solve the manager’s problem.
 

 

Input
The input consists of T test cases. The number of test cases ) (T is given in the first line of the input. Each test case begins with a line containing an integer N , 1<=N<=200 , that represents the number of tables to move. Each of the following N lines contains two positive integers s and t, representing that a table is to move from room number s to room number t (each room number appears at most once in the N lines). From the N+3-rd line, the remaining test cases are listed in the same manner as above.
 

 

Output
The output should contain the minimum time in minutes to complete the moving, one per line.
 

 

Sample Input
3 4 10 20 30 40 50 60 70 80 2 1 3 2 200 3 10 100 20 80 30 50
 

 

Sample Output
10 20 30

【题目来源】

Asia 2001, Taejon (South Korea)

 

题目意思很容易理解,这里就不过多说了。

【题目分析】

贪心算法,我看很多人用区间标记的方法写了一百多行,其实根本不用,直接就统计排序就行,不仅好理解,而且代码也很精简。

 

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#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
int cnt[200];
bool cmp(int a,int b)
{
    return a>b;
}
int main()
{
    int T,n,a,b,l,r;
    scanf("%d",&T);
    while(T--)
    {
        memset(cnt,0,sizeof(cnt));
        scanf("%d",&n);
        for(int i=0;i<n;++i)
        {
            scanf("%d%d",&a,&b);
            l=min(a,b);
            r=max(a,b);
            l=(l+1)/2;
            r=(r+1)/2;
            for(int j=l;j<=r;++j)
                cnt[j]++;
        }
        sort(cnt,cnt+200,cmp);
        printf("%d\n",cnt[0]*10);
    }
    return 0;
}
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贪心 --- 巧妙解法,布布扣,bubuko.com

贪心 --- 巧妙解法

标签:des   style   c   class   blog   code   

原文地址:http://www.cnblogs.com/acmer-jsb/p/3753850.html

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