poj 1164 The Castle dp区域计数水题

标签：poj   算法   dp   

水题，直接贴代码。

//poj 1164
//sep9
#include <iostream>
using namespace std;
int a[64][64];
int dp[64][64];
int n,m;
const int west=1,north=2,east=4,south=8;
void dfs(int x,int y)
{
	dp[x][y]=1;	
	if((a[x][y]&north)==0&&dp[x-1][y]==-1){
		dfs(x-1,y);
		dp[x][y]+=dp[x-1][y];
	}
	if((a[x][y]&south)==0&&dp[x+1][y]==-1){
		dfs(x+1,y);
		dp[x][y]+=dp[x+1][y];
	}
	if((a[x][y]&west)==0&&dp[x][y-1]==-1){
		dfs(x,y-1);
		dp[x][y]+=dp[x][y-1];	
	}
	if((a[x][y]&east)==0&&dp[x][y+1]==-1){
		dfs(x,y+1);
		dp[x][y]+=dp[x][y+1];
	}
	return ;
}

int main()
{
	scanf("%d%d",&n,&m);
	int i,j;
	for(i=1;i<=n;++i)
		for(j=1;j<=m;++j)
			scanf("%d",&a[i][j]); 	
	memset(dp,-1,sizeof(dp));
	int room_num=0,max_room=1;
	for(i=1;i<=n;++i)
		for(j=1;j<=m;++j)
			if(dp[i][j]==-1){
				++room_num;
				dfs(i,j);
				max_room=max(max_room,dp[i][j]);
			}
	printf("%d\n%d\n",room_num,max_room);
	return 0;
}

poj 1164 The Castle dp区域计数水题

标签：poj   算法   dp   

原文地址：http://blog.csdn.net/sepnine/article/details/43033519