标签:style class code ext width color string int html set htm
给定2^n 支足球队进行比赛,n<=7. 队伍两两之间有一个获胜的概率,求每一个队伍赢得最后比赛的概率是多少?
状态其实都是很显然的,一开始觉得这个问题很难啊,不会。dp[i][j] 表示第i支队伍赢得前j轮比赛的概率。(这个题目处理区间的时候比较恶心,小心点即可)。
1:
2: #include <iostream>
3: #include <cstdio>
4: #include <cstring>
5: #include <map>
6: #include <algorithm>
7: using namespace std;
8:
9: double p[135][135];
10: double dp[135][10];
11:
12: pair<int,int> range(int idx, int round)
13: {
14: int x = (idx>>round) ^1;
15: return make_pair(x<<round, (x<<round) + (1<<(round)) - 1);
16: }
17: int main()
18: {
19: // freopen("1.txt","r",stdin);
20: int n;
21: while(cin>>n && n !=-1)
22: {
23: for(int i=0; i<(1<<n); i++)
24: {
25: for(int j=0; j<(1<<n); j++)
26: {
27: cin>>p[i][j];
28: }
29: }
30: memset(dp,0,sizeof(dp));
31: for(int i=0; i< (1<<n); i++)
32: {
33: dp[i][0] = p[i][i^1];
34: }
35: for(int round=1; round<n; round++) // round
36: {
37: for(int j=0; j< (1<<n); j++)
38: {
39: pair<int,int> r = range(j, round);
40: for(int k = r.first; k<= r.second; k++)
41: {
42: dp[j][round] += p[j][k] *dp[k][round - 1]*dp[j][round-1];
43: }
44: }
45: }
46: int idx = -1;
47: double ret = 0;
48: double sum = 0;
49: for(int i=0; i<(1<<n); i++)
50: {
51: sum+= dp[i][n-1];
52: if(dp[i][n-1] > ret)
53: {
54: idx = i;
55: ret = dp[i][n-1];
56: }
57: }
58: cout<<idx+1<<endl;
59: }
60: }
标签:style class code ext width color string int html set htm
原文地址:http://www.cnblogs.com/sosi/p/3701410.html