题目链接:http://poj.org/problem?id=1251
简单题
#include <stdio.h> #include <iostream> #include <string.h> #include <algorithm> #include <math.h> #include <stack> #include <queue> using namespace std; #define INF 10000000 int n, m; char a[5], b[5]; int c, d; int map[100][100], dis[100], v[100]; int prim(int n) { int i, j, k, min, sum = 0; for (i = 1; i <= n; i++) dis[i] = map[1][i]; memset(v, 0, sizeof(v)); v[1] = 1; dis[1] = 0; for (i = 2; i <= n; i++) { k = 1; min = INF; for (j = 1; j <= n; j++) if (!v[j] && min>dis[j]) { k = j; min = dis[j]; } sum += min; v[k] = 1; for (j = 1; j <= n; j++) if (!v[j] && dis[j]>map[k][j]) dis[j] = map[k][j]; } return sum; } int main() { while (scanf("%d",&n) != EOF) { if (n == 0) break; for (int i = 1; i <= n; i++) for (int j = 1; j <= n; j++) { if (i != j) map[i][j] = INF; else map[i][j]= 0; } m = n-1; while (m--) { scanf("%s %d",a,&c); while (c --) { scanf("%s %d",b,&d); if (map[a[0]-'A'+1][b[0]-'A'+1] > d) { map[a[0]-'A'+ 1][b[0]-'A'+1] = d; map[b[0]-'A'+1][a[0]-'A'+1] = d; } } } printf("%d\n",prim(n)); } return 0; }
原文地址:http://blog.csdn.net/u014427196/article/details/43114479