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leetcode 27. Remove Element

时间:2015-01-25 22:33:24      阅读:150      评论:0      收藏:0      [点我收藏+]

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Given an array and a value, remove all instances of that value in place and return the new length.

The order of elements can be changed. It doesn‘t matter what you leave beyond the new length.

 1 int removeElement(int A[], int n, int elem) 
 2     {
 3         int fast = 0, slow = 0;
 4         
 5         while (fast < n)
 6         {
 7             if (elem != A[fast])
 8             {
 9                 A[slow] = A[fast];
10                 slow++;
11             }
12             fast++;
13         }
14         
15         return slow;
16     }

 

leetcode 27. Remove Element

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原文地址:http://www.cnblogs.com/ym65536/p/4249063.html

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