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http://poj.org/problem?id=1384
题意:给出一个储蓄罐 的空和满时的重量
再给出n种硬币的 value 和 weight
问满足正好装满罐子时的最小价值是多少
思路 :
if(dp[j]>dp[j-w[i]]+v[i]) dp[j]=dp[j-w[i]]+v[i];
#include<cstdio> #include<cstring> #include<cmath> #include<iostream> #include<algorithm> using namespace std; int main() { int e,f; int n,t; int i,j,k; int INF=1000000000; int v[1000],w[1000]; int dp[10000+100]; scanf("%d",&t); while(t--) { scanf("%d%d",&e,&f); f=f-e; scanf("%d",&n); for(i=1;i<=n;i++) scanf("%d%d",&v[i],&w[i]); for(i=1;i<=f;i++) dp[i]=INF; dp[0]=0; for(i=1;i<=n;i++) { for(j=w[i];j<=f;j++) { if(dp[j]>dp[j-w[i]]+v[i]) dp[j]=dp[j-w[i]]+v[i]; } } if(dp[f]<INF) printf("The minimum amount of money in the piggy-bank is %d.\n",dp[f]); else printf("This is impossible.\n"); } return 0; }
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原文地址:http://www.cnblogs.com/sola1994/p/4250270.html