标签:
基本动态规划题
代码:
1 int minPathSum(vector<vector<int> > &grid) { 2 if (grid.empty() || grid[0].empty()) return 0; 3 4 int m = grid.size(); 5 int n = grid[0].size(); 6 vector<int> sum(n, 0); 7 8 sum[n - 1] = grid[m - 1][n - 1]; 9 for (int j = n - 2; j >= 0; j--) 10 sum[j] = grid[m - 1][j] + sum[j + 1]; 11 12 for (int i = m - 2; i >= 0; i--) { 13 sum[n - 1] += grid[i][n - 1]; 14 for (int j = n - 2; j >= 0; j--) 15 sum[j] = min(sum[j], sum[j + 1]) + grid[i][j]; 16 } 17 18 return sum[0]; 19 }
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原文地址:http://www.cnblogs.com/boring09/p/4253736.html