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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 15396 Accepted Submission(s): 9830
代码如下:
1 #include <iostream> 2 using namespace std; 3 4 bool is_leapyear(int n) 5 { 6 if((n % 4 == 0) && (n % 100 != 0)) 7 return true; 8 else if(n % 400 == 0) 9 return true; 10 else if((n % 3200 == 0) && (n % 172800 == 0)) 11 return true; 12 else 13 return false; 14 } 15 16 int main() 17 { 18 int T,i,start,num; 19 cin>>T; 20 while(T--) 21 { 22 cin>>start>>num; 23 if(is_leapyear(start) == true) 24 i = 1; 25 else 26 i = 0; 27 start++; 28 while(i < num) 29 { 30 if(is_leapyear(start) == true) 31 i++; 32 start++; 33 } 34 cout<<start-1<<endl; 35 } 36 return 0; 37 }
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原文地址:http://www.cnblogs.com/baichenjia/p/4254569.html