leetcode 160: Read N Characters Given Read4 II - Call multiple times

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The API: int read4(char *buf) reads 4 characters at a time from a file.

The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file.

By using the read4 API, implement the function int read(char *buf, int n) that reads n characters from the file.

The read function may be called multiple times.

[分析]

用一个cache 和 一个指针, 不够就read4

[CODE]

// Forward declaration of the read4 API.
int read4(char *buf);

class Solution {
public:
    /**
     * @param buf Destination buffer
     * @param n   Maximum number of characters to read
     * @return    The number of characters read
     */
    char cache[4];
    int p = -1;
    int r = 0;

    int read(char *buf, int n) {
        if(n<=0) return 0;
        int s = n;
        if(p==-1) {
            r = read4(cache);
            p = 0;
        }
        
        while(n>0 && p<r) {
            *buf = cache[p];
            ++buf;
            n--;
            p++;
            if(p==r) {
                r = read4(cache);
                p = 0;
            }
        }
        
        return s - n;
        
        
    }
};

leetcode 160: Read N Characters Given Read4 II - Call multiple times

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原文地址：http://blog.csdn.net/xudli/article/details/43225571