题目链接:ZigZag Conversion
The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H N
A P L S I I G
Y I R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string text, int nRows);
convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".
这道题的要求是对字符串进行ZigZag转化。举个例子:
A G M
B F H L N
C E I K O
D J P
由ABCDEFGHIJKLMNOP转化成AGMBFHLNCEIKODJP。
理解了题意,就变得简单了。在转化的时候,可以按垂直方向生成字符串,然后按水平方向读取字符串。
时间复杂度:O(n)
空间复杂度:O(1)
1 class Solution
2 {
3 public:
4 string convert(string s, int nRows)
5 {
6 vector<string> v(nRows);
7 for(int i = 0; i < s.size(); )
8 {
9 for(int j = 0; i < s.size() && j < nRows; ++i, ++j)
10 v[j] += s[i];
11 for(int j = nRows-2; i < s.size() && j > 0; ++i, --j)
12 v[j] += s[i];
13 }
14
15 string res = "";
16 for(int i = 0; i < nRows; ++i)
17 res += v[i];
18 return res;
19 }
20 };
转载请说明出处:LeetCode --- 6. ZigZag Conversion
LeetCode --- 6. ZigZag Conversion
原文地址:http://blog.csdn.net/makuiyu/article/details/43228867