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The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H N A P L S I I G Y I R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string text, int nRows);
convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".
简单来说就是把一个字符串变成一个倒Z字形，然后一行一行输出
public class Solution { public String convert(String s, int nRows) { ArrayList<ArrayList<String>> allList = new ArrayList<ArrayList<String>>();//用于存放ZigZag后的二维字符数组 char[] char_array = s.toCharArray(); int size = char_array.length;//字符总长度 if(size<=nRows||nRows==1){ return s; } for(int i=0;i<nRows;i++){//初始化allList ArrayList<String> list = new ArrayList<String>(); allList.add(list); } int x = 0,y = 0;//二维坐标（初始点为(0,0)） int stepX = 0,stepY = 1;//2个坐标上的增量 int value = 2*nRows-2; for(int n=0;n<size;n++){ String letter = String.valueOf(char_array[n]); allList.get(y).add(letter); if(n%value == 0){ stepX = 0; stepY = 1; } else if(n%value == nRows-1){ stepX = 1; stepY = -1; } y = y+stepY;//跟新坐标 } String result = ""; for(int j=0;j<nRows;j++){ ArrayList<String> lists = allList.get(j); for(String list:lists){ result = result+list; } } return result; } }
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原文地址：http://www.cnblogs.com/mrpod2g/p/4256653.html
