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There are two sorted arrays A and B of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)).
用二分的方法求合并数组的中值。用找第k大的值来求,不断去掉较小的一半,解法很妙。
class Solution { public: double kthNum(int A[], int m, int B[], int n, int k){ if(m > n) return kthNum(B,n,A,m,k); if(m == 0) return B[k-1]; if(k == 1) return min(A[0],B[0]); int pa = min(k/2,m), pb = k - pa; if(A[pa-1] < B[pb-1]) return kthNum(A+pa,m-pa,B,n,k-pa); else if(A[pa-1] > B[pb-1]) return kthNum(A,n,B+pb,n-pb,k-pb); else return A[pa-1]; } double findMedianSortedArrays(int A[], int m, int B[],int n){ if((m+n)&1) return kthNum(A,m,B,n,(m+n)/2+1); else return (kthNum(A,m,B,n,(m+n)/2)+kthNum(A,m,B,n,(m+n)/2+1)) /2; } };
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原文地址:http://blog.csdn.net/sina012345/article/details/43268537