标签:
动态规划题,注意0导致的小陷阱。
代码:
1 int numDecodings(string s) { 2 if (s.empty() || s[0] < ‘1‘ || s[0] > ‘9‘) return 0; 3 4 int sum = s[s.length() - 1] >= ‘1‘ && s[s.length() - 1] <= ‘9‘ ? 1 : 0; 5 int nextnext = 1; 6 int next = sum; 7 8 for (int i = s.length() - 2; i >= 0; i--) { 9 if (s[i] >= ‘0‘ && s[i] <= ‘9‘) { 10 if (s[i] == ‘1‘ || (s[i] == ‘2‘ && s[i + 1] >= ‘0‘ && s[i + 1] <= ‘6‘)) 11 sum = next + nextnext; 12 else if (s[i] == ‘0‘) 13 sum = 0; 14 else 15 sum = next; 16 nextnext = next; 17 next = sum; 18 } 19 else 20 return 0; 21 } 22 23 return sum; 24 }
标签:
原文地址:http://www.cnblogs.com/boring09/p/4259364.html