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Time Limit: 15000/8000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 6389 Accepted Submission(s): 2025
#include<iostream> #include<cstring> #include<string> #include<cmath> #include<algorithm> #include<cstdlib> #include<cstdio> #include<set> using namespace std; #define maxn 1000010 set<int> S; int n,m,fa[maxn],id[maxn]; char s[2]; int find(int x) { if(x!=fa[x]) fa[x]=find(fa[x]); return fa[x]; } void Union(int x,int y) { int fx,fy; fx=find(x),fy=find(y); if(fx!=fy) { fa[fx]=fy; } } int main() { int tt,a,b,cas=1; while(scanf("%d%d",&n,&m)!=EOF) { if(n==0&&m==0) break; for(int i=0;i<=n;i++) fa[i]=i,id[i]=i; int k=n+1; for(int i=0;i<m;i++) { scanf("%s",s); if(s[0]==‘M‘) { scanf("%d%d",&a,&b); Union(id[a],id[b]); } else if(s[0]==‘S‘) { scanf("%d",&tt); id[tt]=k; fa[id[tt]]=id[tt]; k++; } } S.clear(); for(int i=0;i<n;i++) { S.insert(find(id[i])); } printf("Case #%d: %d\n",cas,S.size()); cas++; } return 0; }
元素中删除操作,另开一个数组映射一下就ok
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原文地址:http://www.cnblogs.com/a972290869/p/4260500.html