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Time Limit: 15000/8000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 6389 Accepted Submission(s): 2025
#include<iostream>
#include<cstring>
#include<string>
#include<cmath>
#include<algorithm>
#include<cstdlib>
#include<cstdio>
#include<set>
using namespace std;
#define maxn 1000010
set<int> S;
int n,m,fa[maxn],id[maxn];
char s[2];
int find(int x)
{
if(x!=fa[x])
fa[x]=find(fa[x]);
return fa[x];
}
void Union(int x,int y)
{
int fx,fy;
fx=find(x),fy=find(y);
if(fx!=fy)
{
fa[fx]=fy;
}
}
int main()
{
int tt,a,b,cas=1;
while(scanf("%d%d",&n,&m)!=EOF)
{
if(n==0&&m==0)
break;
for(int i=0;i<=n;i++)
fa[i]=i,id[i]=i;
int k=n+1;
for(int i=0;i<m;i++)
{
scanf("%s",s);
if(s[0]==‘M‘)
{
scanf("%d%d",&a,&b);
Union(id[a],id[b]);
}
else if(s[0]==‘S‘)
{
scanf("%d",&tt);
id[tt]=k;
fa[id[tt]]=id[tt];
k++;
}
}
S.clear();
for(int i=0;i<n;i++)
{
S.insert(find(id[i]));
}
printf("Case #%d: %d\n",cas,S.size());
cas++;
}
return 0;
}
元素中删除操作,另开一个数组映射一下就ok
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原文地址:http://www.cnblogs.com/a972290869/p/4260500.html