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Determine whether an integer is a palindrome. Do this without extra space.
方法一:
public class Solution { public boolean isPalindrome(int x) { String str = x+""; char[] charArray = str.toCharArray(); int size = charArray.length; for(int i=0;i<size/2;i++){ if(charArray[i]!=charArray[size-1-i]){ return false; } } return true; } }
这里用了一个额外的数组charArray,但最后也Accept了。
方法二:
public class Solution { public boolean isPalindrome(int x) { if(x<0){ return false; } if(x==0){ return true; } int e = 1; while(x/e>=10){ e = e*10; } int highDigit,lowDigit; while(x!=0){ highDigit = x/e; lowDigit = x%10; if(highDigit!=lowDigit){ return false; } x = x-highDigit*e; x = x/10; e = e/100; } return true; } }
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原文地址:http://www.cnblogs.com/mrpod2g/p/4261166.html